हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Choose the correct alternative: The equation tan–1x – cot–1x = tan-1(13) has

Advertisements
Advertisements

प्रश्न

Choose the correct alternative:

The equation tan–1x – cot1x = `tan^-1 (1/sqrt(3))` has

विकल्प

  • no solution

  • unique solution

  • two solutions

  • infinite number of solutions

MCQ
Advertisements

उत्तर

unique solution

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Inverse Trigonometric Functions - Exercise 4.6 [पृष्ठ १६८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.6 | Q 17 | पृष्ठ १६८

संबंधित प्रश्न

If a line makes angles 90°, 60° and θ with x, y and z-axis respectively, where θ is acute, then find θ.


Prove `tan^(-1)  2/11 + tan^(-1)  7/24 = tan^(-1)  1/2`


Write the following function in the simplest form:

`tan^(-1)  (sqrt(1 + x^2) - 1)/x, x ≠ 0`


Write the following function in the simplest form:

`tan^(-1)  x/(sqrt(a^2 - x^2)), |x| < a`


Prove that `cos^(-1)  12/13 + sin^(-1)  3/5 = sin^(-1)  56/65`.


Solve for x : \[\tan^{- 1} \left( \frac{x - 2}{x - 1} \right) + \tan^{- 1} \left( \frac{x + 2}{x + 1} \right) = \frac{\pi}{4}\] .


Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 (cos pi)`


Prove that `tan^-1x + tan^-1  (2x)/(1 - x^2) = tan^-1  (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`


Choose the correct alternative:

`sin^-1  3/5 - cos^-1  13/13 + sec^-1  5/3 - "cosec"^-1  13/12` is equal to


Show that `tan(1/2 sin^-1  3/4) = (4 - sqrt(7))/3` and justify why the other value `(4 + sqrt(7))/3` is ignored?


If a1, a2, a3,...,an is an arithmetic progression with common difference d, then evaluate the following expression.

`tan[tan^-1("d"/(1 + "a"_1 "a"_2)) + tan^-1("d"/(21 + "a"_2 "a"_3)) + tan^-1("d"/(1 + "a"_3 "a"_4)) + ... + tan^-1("d"/(1 + "a"_("n" - 1) "a""n"))]`


The maximum value of sinx + cosx is ____________.


The value of expression 2 `"sec"^-1  2 + "sin"^-1 (1/2)`


sin (tan−1 x), where |x| < 1, is equal to:


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


If `"sin"^-1 (1 - "x") - 2  "sin"^-1 ("x") = pi/2,` then x is equal to ____________.


If sin–1x + sin–1y + sin–1z = π, show that `x^2 - y^2 - z^2 + 2yzsqrt(1 - x^2) = 0`


Solve:

sin–1 (x) + sin–1 (1 – x) = cos–1 x


If \[\tan^{-1}\left(\frac{x}{2}\right)+\tan^{-1}\left(\frac{y}{2}\right)+\tan^{-1}\left(\frac{z}{2}\right)=\frac{\pi}{2}\]  then xy + yz + zx =


`sin (tan^-1  4/5 + tan^-1  4/3 + tan^-1  1/9 - tan^-1  1/7)` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×