हिंदी

State the Electronic Configuration of Hydrogen (At. No. 1).E Give a Reason Why Hydrogen Can Be Placed in Group 1 (1a) and Group 17 (Viia) of the Periodic Table.

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प्रश्न

State the electronic configuration of hydrogen [at. no. 1].e
Give a reason why hydrogen can be placed in group 1 [1A] and group 17 [VIIA] of the periodic table.

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उत्तर

Electronic configuration of hydrogen is 1 i.e. it has le, IP in nucleus. Hydrogen can be placed in group 1[1A] as it forms a positive ion as in HC1 like alkali metals H

 - 1e- → H1+ 

Li - 1e- → Li1+ Na - 1e- = Na1+

It can be placed in group 17 [VIIA]

As it can form a negative ion as in NaH like Halogens H + 1e- → H1- 

Cl + 1e- → Cl1- 

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Preparation of Hydrogen
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अध्याय 6: Study of The First Element - Hydrogen - Additional Questions

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विराफ जे दलाल Simplified ICSE Chemistry [English] Class 9
अध्याय 6 Study of The First Element - Hydrogen
Additional Questions | Q 1

संबंधित प्रश्न

Give reason for the following:

Dilute sulphuric acid cannot be replaced by concentrated acid in the preparation of hydrogen.


Hydrogen may be prepared in the laboratory by the action of a metal on an acid.

Which of the acids dilute sulphuric, concentrated sulphuric, dilute nitric acid and concentrated nitric acid would you choose? Explain why you would not use the acids you reject.


Complete and balance the following reaction.

Fe + HCl →_____________ +___________


Starting from hydrogen gas how would you obtain a basic gas.


Select the correct options for the following statement:

The product formed on combustion of hydrogen in air is ___.


Complete and balance the equation:

[General method]

Reactions of metals with steam

Iron - 3Fe + 4H2O ⇌ ______+ _______ [g]


Complete and balance the equation:

[General method]

Reactions of metals with dilute acids

Iron - Fe + 2HCl → ______ + _______ [g]


Complete and balance the equation:

[General method]

Reactions of metals - alkali [conc. soln.]

Lead - Pb + 2NaOH → ______ + _______ [g]


Complete and balance the equation:

[Industrial Method - Bosch process]

  • Step I - Production of water gas -
    \[\ce{C + H2O->[1000°C]}\] [____ + ____] - Δ
  • Step II - Reduction of steam to hydrogen by carbon monoxide
    \[\ce{CO + H2 + H2O->[450°C][Fe2O3]}\] _____ + ____ [g]
  • Step III - Removal of unreacted carbon dioxide and carbon monoxidefrom the above mixture
    KOH + CO2 → _________ + ______ 
    CuCl + CO + 2H2O → _______

State the reactant added to hydrogen to obtain the respective product in following case.

Hydrogen sulphide


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