Question

Solve the given inequality for real x : `x/3 > x/2 + 1`

Answer 1

The given inequality `x/3 > x/2 + 1`

`x/3 -  x/2  > 1`

or  `(2x - 3x)/6 > 1`

= `-x/6 > 1`

-On multiplying by 6,

x < - 6

Thus, all real numbers x, which are less than -6, are the solutions of the given inequality.

Hence, the solution set of the given inequality is (–∞, –6).