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प्रश्न
Solve for x, the inequality given below.
4x + 3 ≥ 2x + 17, 3x – 5 < –2
योग
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उत्तर
4x + 3 ≥ 2x + 17
⇒ 4x – 2x ≥ 17 – 3
⇒ 2x ≥ 14
⇒ x ≥ 7 ......(i)
Also,
3x – 5 < –2
⇒ 3x < 3
⇒ x < 1 .....(ii)
Since, equations (i) and (ii) cannot be possible, simultaneously We conclude that x has no solution.
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