Question

सोडवा: `intx^9 . sec^2 (x^10) dx`

Answer 1

मानूया I = `int x^9 .sec^2(x^10).dx`

x¹⁰ = t असे ठेवूया

∴ 10x⁹dx = dt

∴ x⁹dx = `(1)/(10)dt`

∴ I = `int sec^2t.dt/(10)`

= `1/10 int sec^2t  dt`

= `(1)/(10)tan t+ c`

= `(1)/(10)tan(x^10) + c`