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प्रश्न
Simplify:
`(125"x"^-3)^(1/3)`
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उत्तर
`(125"x"^-3)^(1/3)`
`=(125)^(1/3) * "x"^(-3xx1/3) ...(because ("a"^"m")^"n" = "a"^("m" xx "n") "and" " a"^"m" xx "a"^"n" = "a"^("m" xx "n"))`
`=(5xx5xx5)^(1/3)."x"^-1`
`= (5^3)^(1/3) * x^-1`
`= (5^cancel(3))^(1/cancel(3)) * x^-1`
= `5x^-1`
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संबंधित प्रश्न
Compute:
`(12)^-2xx3^3`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Evaluate:
`8^0+4^0+2^0`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`5"z"^16÷15"z"^-11`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
