Advertisements
Advertisements
प्रश्न
Simplify:
`(125"x"^-3)^(1/3)`
योग
Advertisements
उत्तर
`(125"x"^-3)^(1/3)`
`=(125)^(1/3) * "x"^(-3xx1/3) ...(because ("a"^"m")^"n" = "a"^("m" xx "n") "and" " a"^"m" xx "a"^"n" = "a"^("m" xx "n"))`
`=(5xx5xx5)^(1/3)."x"^-1`
`= (5^3)^(1/3) * x^-1`
`= (5^cancel(3))^(1/cancel(3)) * x^-1`
= `5x^-1`
shaalaa.com
More About Exponents
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`9^0xx4^-1÷2^-4`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
Evaluate:
`(4"x")^0`
Simplify:
`5"z"^16÷15"z"^-11`
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
