Advertisements
Advertisements
प्रश्न
Simplify: a5 ÷ a3 + 3a × 2a
योग
Advertisements
उत्तर
a5 ÷ a3 + 3a × 2a
= a5−3 + 3a × 2a
= a2 + 6a2
= 7a2
shaalaa.com
Simplification of Expressions
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Evaluate : `(64)^(2/3) - root(3)(125) - 1/2^(-5) + (27)^(-2/3) xx (25/9)^(-1/2)`
If `[ 9^n. 3^2 . 3^n - (27)^n]/[ (3^m . 2 )^3 ] = 3^-3`
Show that : m - n = 1.
If 34x = ( 81 )-1 and `10^(1/y) = 0.0001, "Find the value of " 2^(- x ) xx 16^y `
Prove that : `( a + b + c )/( a^-1b^-1 + b^-1c^-1 + c^-1a^-1 ) = abc`
Simplify : `"p"^2"x"-2{"px"-3"x"("x"^2-overline(3"a"-"x"^2))}`
Simplify: x5 ÷ (x2 × y2) × y3
Simplify: (y3 − 5y2) ÷ y × (y − 1)
Write each of the following in the simplest form:
a-3 x a2 x a0
Simplify the following:
`(81)^(3/4) - (1/32)^(-2/5) + 8^(1/3).(1/2)^-1. 2^0`
Simplify the following:
`(27/343)^(2/3) ÷ (1)/(625/1296)^(1/4) xx (536)/root(3)(27)`
