Advertisements
Advertisements
प्रश्न
Simplify: x5 ÷ (x2 × y2) × y3
योग
Advertisements
उत्तर
x5 ÷ (x2 × y2) × y3
`="x"^5/("x"^2"y"^2)xx"y"^3`
= x5−2 − y3−2
= x3y
shaalaa.com
Simplification of Expressions
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Evaluate : `(64)^(2/3) - root(3)(125) - 1/2^(-5) + (27)^(-2/3) xx (25/9)^(-1/2)`
Solve for x : (13)√x = 44 - 34 - 6
Evaluate : `((x^q)/(x^r))^(1/(qr)) xx ((x^r)/(x^p))^(1/(rp)) xx ((x^p)/(x^q))^(1/(pq))`
Simplify : `2{m-3(n+overline(m-2n))}`
Simplify : `"p"^2"x"-2{"px"-3"x"("x"^2-overline(3"a"-"x"^2))}`
Simplify the following and express with positive index:
3p-2q3 ÷ 2p3q-2
Simplify the following:
`(8 xx^6y^3)^(2/3)`
Simplify the following:
`((36"m"^-4)/(49"n"^-2))^(-3/2)`
Simplify the following:
`(81)^(3/4) - (1/32)^(-2/5) + 8^(1/3).(1/2)^-1. 2^0`
Simplify the following:
`(27/343)^(2/3) ÷ (1)/(625/1296)^(1/4) xx (536)/root(3)(27)`
