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Show that the Slope of the P−V Diagram is Greater for an Adiabatic Process Compared to an Isothermal Process. - Physics

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प्रश्न

Show that the slope of the p−V diagram is greater for an adiabatic process compared to an isothermal process.

संक्षेप में उत्तर
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उत्तर

In an isothermal process, 
PV = k     ...(i)
On differentiating it w.r.t V, we get

`"V" (dP)/(dV) + "P" = 0`

`(dP)/(dV) = -"P"/"V"`

`(dP)/(dV) = - "k"/"V"^2` [ Using (i)] , k = constant  

k = constant
In an adiabatic process, 

PVγ = K ...(ii)

On differentiating it w.r.t V, we get

`"V"^gamma(d"P")/(d"V")+ gamma"PV"^(gamma-1) = 0`

`(d"P")/(d"V") = -( gamma "P""V"^(gamma-1))/"V" ^ (gamma+1)    ["Using"  (ii) , γ > 1 ]` and

K is constant

`gamma and (d"P")/(d"V")` 

are the slope of the curve and the ratio of heat capacities at constant pressure and volume, respectively; P  is pressure and V is volume of the system. 
By comparing the two slopes and keeping in mind that γ >1 , we can see that the slope of the P-V diagram is greater for an adiabatic process than an isothermal process.

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अध्याय 5: Specific Heat Capacities of Gases - Short Answers [पृष्ठ ७६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 5 Specific Heat Capacities of Gases
Short Answers | Q 7 | पृष्ठ ७६

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