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Show That F(X) = Tan X Is an Increasing Function on (−π/2, π/2) ?

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प्रश्न

Show that f(x) = tan x is an increasing function on (−π/2, π/2) ?

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उत्तर

\[f\left( x \right) = \tan x\]

\[f'\left( x \right) = \sec^2 x\]

\[\text { Here },\]

\[\frac{- \pi}{2} < x < \frac{\pi}{2}\]

\[ \Rightarrow \sec x > 0 \left[ \because Sec \text { function is positive in first and fourth quadrant } \right]\]

\[ \Rightarrow \sec^2 x > 0\]

\[ \Rightarrow f'\left( x \right) > 0, \forall x \in \left( \frac{- \pi}{2}, \frac{\pi}{2} \right)\]

\[\text { So },f(x)\text { is increasing on } \left( \frac{- \pi}{2}, \frac{\pi}{2} \right) .\]

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अध्याय 16: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 14 | पृष्ठ ३४

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