Question

Show how is the following alcohol prepared by the reaction of a suitable Grignard reagent on methanal?

\[\begin{array}{cc}
\ce{CH3 - CH - CH2OH}\\
|\phantom{......}\\
\ce{CH3}\phantom{...}
\end{array}\]

Answer 1

\[\begin{array}{cc}
\phantom{..........}\ce{OMgBr}\\
\phantom{....}|\\
\ce{CH3 - CH - MgBr + HCHO -> CH3 - CH - CH2 ->[H2O] CH3 - CH - CH2OH + Mg(OH)Br}\\
|\phantom{.................................}|\phantom{......................}|\phantom{...................}\\
\phantom{.}\ce{CH3}\phantom{.............................}\ce{CH3}\phantom{...................}\ce{CH3}\phantom{.................}
\end{array}\]