Advertisements
Advertisements
प्रश्न
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Advertisements
उत्तर
We have to prove that `sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Let x = `sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)`
`=sqrt(1/2^2)+((0.01xx100)/(1xx100))^(-1/2)-(3^3)^(2/3)`
`=1/2+1/(100)^(-1/2)-3^(3xx2/3)`
`=1/2+1/(1/100^(1/2))-3^2`
`=1/2+1/(1/(10xx10)^(1/2))-3^2`
`=1/2+1/(1/10^(2xx1/2))-3^2`
`=1/2+1/(1/10)-3^2`
`=1/2+1xx10/1-3xx3`
`=1/2+10-9`
`=3/2`
Hence, `sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt(x^-3))^5`
State the quotient law of exponents.
Write the value of \[\sqrt[3]{125 \times 27}\].
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
If x-2 = 64, then x1/3+x0 =
If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]
If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is
The positive square root of \[7 + \sqrt{48}\] is
Find:-
`125^((-1)/3)`
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
