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Prove That: Sin ( a + B ) + Sin ( a − B ) Cos ( a + B ) + Cos ( a − B ) = Tan a

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प्रश्न

Prove that: \[\frac{\sin \left( A + B \right) + \sin \left( A - B \right)}{\cos \left( A + B \right) + \cos \left( A - B \right)} = \tan A\]

संक्षेप में उत्तर
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उत्तर

\[\text{ LHS }= \frac{\sin\left( A + B \right) + \sin\left( A - B \right)}{\cos\left( A + B \right) + \cos\left( A - B \right)}\]
\[ = \frac{\sin A \cos B + \cos A \sin B + \sin A \cos B - \cos A \sin B}{\cos A \cos B - \sin A \sin B + \cos A \cos B + \sin A \sin B}\]
\[ = \frac{2\sin A \cos B}{2\cos A \cos B}\]
\[ = \frac{\sin A}{\cos A}\]
\[ = \tan A\]
 = RHS
Hence proved .

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अध्याय 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.1 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.1 | Q 16.1 | पृष्ठ २०

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