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Potassium Sulphite on Reacting with Hydrochloric Acid Releases _______ Gas

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प्रश्न

Potassium sulfite on reacting with hydrochloric acid releases _______ gas. (Cl2, SO2, H2S)

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Notes

Potassium sulfite on reacting with hydrochloric acid releases SO2 gas

 

General Preparation of Hydrogen Chloride Gas
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2016-2017 (March) Set 1

संबंधित प्रश्न

Write a balanced equation for the action of dilute hydrochloric acid on sodium sulphide.


Explain why anhydrous HCl is a poor conductor while aqueous HCl is an excellent conductor.


Write an equation for the reaction of hydrochloric acid on zinc carbonate.


Name the following:
Five oxidizing agents that liberated chlorine from concentrated hydrochloric acid.


What would happen if
Calcium oxide is used to dry hydrogen chloride.


  1. What must be added to sodium chloride to prepare hydrogen chloride?
  2. Write the equation for the reaction which takes place in question (a).

Select from the list given (a to e) one substances in each case which matches the description given in parts (i) to (v). (Note : Each substance is used only one in the answer)
(a) Nitroso Iron (II) Sulphate
(b) Iron (III) chloride
(c) Chromium sulphate
(d) Lead (II) chloride
(e) Sodium chloride
(i) A compound which is deliquescent
(ii) A compound which is insoluble in cold water, but soluble in hot water
(iii) The compound responsible for the brown ring during the brown ring test of nitrate iron
(iv) A compound whose aqueous solution is neutral in nature
(v) The compound which is responsible for the green colouration when sulphur dioxide is passed through acidified potassium dichromate solution


Give a chemical test to distinguish between the following pair of compounds:

Hydrogen chloride gas and hydrogen sulphide gas


State your observation when:

Decomposition of bicarbonates by dil. H2SO4

2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + 2CO2

2KHCO3 + H2SO4 → K2SO4 + 2H2O + 2CO2


State which of the two - a solution of HCl in water or in toluene is an electrolyte. Explain.


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