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P a Particle Executes Simple Harmonic Motion Under the Restoring Force Provided by a Spring. the Time Period is T.

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प्रश्न

A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part is used to continue the simple harmonic motion, the time period will

विकल्प

  • remain T

  • become 2T

  • become T/2

  • become \[T/\sqrt{2}\]

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उत्तर

become \[T/\sqrt{2}\]

Time period \[\left( T \right)\] is given by,

\[T = 2\pi\sqrt{\frac{m}{k}}\]

where m is the mass, and
          k is spring constant.

When the spring is divided into two parts, the new spring constant k1 is given as,
k1 =\[2k\]

New time period T1 :
T1  = \[2\pi\sqrt{\frac{m}{2k}} = \frac{1}{\sqrt{2}}2\pi\sqrt{\frac{m}{k}} = \frac{1}{\sqrt{2}}T\]

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अध्याय 12: Simple Harmonics Motion - MCQ [पृष्ठ २५१]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 12 Simple Harmonics Motion
MCQ | Q 14 | पृष्ठ २५१

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