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प्रश्न
A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part is used to continue the simple harmonic motion, the time period will
विकल्प
remain T
become 2T
become T/2
become \[T/\sqrt{2}\]
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उत्तर
become \[T/\sqrt{2}\]
Time period \[\left( T \right)\] is given by,
\[T = 2\pi\sqrt{\frac{m}{k}}\]
where m is the mass, and
k is spring constant.
When the spring is divided into two parts, the new spring constant k1 is given as,
k1 =\[2k\]
New time period T1 :
T1 = \[2\pi\sqrt{\frac{m}{2k}} = \frac{1}{\sqrt{2}}2\pi\sqrt{\frac{m}{k}} = \frac{1}{\sqrt{2}}T\]
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