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प्रश्न
Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
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उत्तर १
CH3CH2 – CH2 –CO –CH3
उत्तर २
Pentan-2-one (CH3-CH2-CH2-CO-CH3) give yellow precipitate of CHI3 with NaOI, thats means it gives iodoform test.
Pentan-3-one (CH3-CH2-CO-CH2-CH3) does not give yellow precipitate with CHI3 with NaOI, so Pentan-3-one does not give iodoform test.
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संबंधित प्रश्न
Which of the following compounds will give butanone on oxidation with alkaline \[\ce{KMnO4}\] solution?
Which sugar does not reduce Fehling's solution?
Acetone and acetaldehyde are differentiated by
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
Which among the above compound/s does/do not form Silver mirror when treated with Tollen's reagent?
In Tollen's test for aldehyde, the overall number of electrons(s) transferred to the Tollen's reagent formula \[\ce{[Ag(NH3)2]+}\] per aldehyde group to form silver mirror is ______. (Round off to the nearest integer)
The reagent that can be used to distinguish acetophenone and benzophenone is ______.
An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and glycol. 'A' forms a dioxime with hydroxylamine and gives a positive iodoform and Tollen's test. Identify 'A' and give its reaction for iodoform and Tollen's test.
Benzaldehyde is obtained from Rosenmund’s reduction of:
Match List-I with List-II:
| List-I (Reaction) |
List-II (Reagents/Condition) |
||
| A. |  |
I. |  |
| B. |  |
II. | CrO3 |
| C. |  |
III. | KMnO4/KOH, Δ |
| D. |  |
IV. | (i) O3 (ii) Zn-H2O |
Choose the correct answer from the options given below:
