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On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.

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प्रश्न

On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.

Write the electronic configuration for d4 ion if ∆0 < P on the basis of crystal field theory.

लघु उत्तरीय
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उत्तर

On the basis of crystal field theory, for a d4 ion, if Δ0 < P, then the complex is a high spin complex formed by the association of weak field ligands with the metal ion. As a result, the fourth electron enters one of the eg orbitals, thereby, exhibiting the electronic configuration \[\ce{t_2g ^3eg^1}\].

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Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
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D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
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Crystal field splitting by various ligands

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[CrA6]3- 13,640 163
[CrB6]3+ 17,830 213
[CrC6]3+ 21,680 259
[CrD6]3- 26,280 314

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(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?

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