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Obtain the expression for the resonant frequency of the LCR series circuit and explain electrical resonance in an LCR series circuit. - Physics

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प्रश्न

Obtain the expression for the resonant frequency of the LCR series circuit and explain electrical resonance in an LCR series circuit.

संक्षेप में उत्तर
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उत्तर

  1. A circuit in which inductance L, capacitance C, and resistance R are connected in series and the circuit admits maximum current corresponding to a given frequency of AC, is called a series resonance circuit.

  2. The impedance (Z) of an LCR circuit is given by,
    Z = `sqrt("R"^2 + (omega"L" - 1/(omega"C"))^2`
  3. At very low frequencies, inductive reactance XL = ωL is negligible but capacitive reactance XC = `1/(omega"L")` is very high. 
  4. As we increase the applied frequency then XL increases and XC decreases. 
  5. At some angular frequency (ωr), XL = XC  
    i.e., ωrL = `1/(omega_"r""C")`
    ∴ `(ω_"r")^2 = 1/"LC" "or"  (2pi"f"_"r")^2 = 1/"LC"`
    ∴ `2pi"f"_"r" = 1/sqrt("LC")`
    ∴ fr = `1/(2pisqrt"LC")`
    Where fr is called the resonant frequency.
  6. At this particular frequency fr, since XL = XC we get Z = `sqrt("R"^2 + 0)` = R.
    This is the least value of Z.
  7. Thus, when the impedance of an LCR circuit is minimum, the circuit is said to be purely resistive, current and voltage are in phase, and hence the current `"i"_0 = "e"_0/"Z" = "e"_0/"R"` is maximum. This condition of the LCR circuit is called resonance condition and this frequency is called series resonant frequency.
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अध्याय 13: AC Circuits - Long Answer

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