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प्रश्न
A particle starting from extreme position performs S.H.M. The phase difference of the particle between any two successive mean positions is ______.
विकल्प
\[\frac{\pi^{c}}{4}\]
\[\frac{\pi^{c}}{2}\]
\[\pi^{c}\]
\[2\pi^{c}\]
MCQ
रिक्त स्थान भरें
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उत्तर
A particle starting from extreme position performs S.H.M. The phase difference of the particle between any two successive mean positions is \[\pi^{c}\].
Explanation:
In S.H.M. starting from extreme position: \[x=A\cos(\omega t)\]
Mean position (x = 0) occurs at phases \[\frac{\pi}{2}\] and \[\frac{3\pi}{2}\] successively.
Phase difference = \[\frac{3\pi}{2}-\frac{\pi}{2}=\pi^c\]
This makes sense as two successive mean positions are half a cycle apart.
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