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प्रश्न
Mr. R.K. Nair gets Rs 6,455 at the end of one year at the rate of 14% per annum in a recurring deposit account. Find the monthly installment.
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उत्तर
Let monthly instalment is Rs P
here n = 1 year = 12 months
n = 12
∵ M.V. = `("n"("n" + 1))/(2 xx 12) xx ("P" xx "R")/(100) + "P"."n"`
⇒ ₹ 6455 = `(12(12 + 1))/(2 xx 12) xx ("P" xx 14)/(100) + "P".12`
₹ 6455 = `(13 xx "P" xx 7)/(100) + "P".12`
⇒ ₹ 6455 = `(91"P" + 1200"P")/(100)`
⇒ ₹ 645500 = 1291P
⇒ P = `(645500)/(1291)`
= ₹ 500.
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Amount Deposited (Rs.) |
Balance (Rs.) |
| Jan 7, 2016 | B/F | 3,000.00 | ||
| Jan 10, 2016 | By Cheque | 2600.00 | 5600.00 | |
| Feb 8, 2016 | To Self | 1500.00 | 4100.00 | |
| Apr 6, 2016 | By Cheque | 2100.00 | 2000.00 | |
| May 4, 2016 | By Cash | 6500.00 | 8500.00 | |
| May 27, 2016 | By Cheque | 1500.00 | 10000.00 |
1) Calculate the interest for the 6 months from January to June 2016, at 6% per annum.
2) If the account is closed on 1st July 2016, find the amount received by the account holder.
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| Date | Particulars | Amount Withdrawn (In Rs) |
Amount Deposits (In Rs) |
Balance (In Rs) |
| Jan 1, 2000 Jan, 8 Feb 18 May 19 July 15 Oct 7 |
By Balance By cash To Cheque By Cash To self By cash |
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| 01.01.2007 | By B/F | 6500.00 | ||
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Deposits (in ₹) |
Balance (in ₹) |
| 1st April 2007 | By Cash | - | 8,550·00 | 8,550·00 |
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