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प्रश्न
Mr. Gupta opened a recurring deposit account in a bank. He deposited Rs. 2500 per month for two years. At the time of maturity he got Rs. 67,500. Find:
1) the total interest earned by Mr Gupta.
2) the rate of interest per annum.
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उत्तर
1) Monthly instalment = Rs. 2500
n = 24, Amount deposited = 2500 x 24 = Rs. 60000
Maturity value = Rs. 67500
Interest on his deposit = Rs. (67500 – 60000) = Rs. 7500
2) Now Interest = `("n"("n"+1))/2 xx ("Instalment" xx "Rate")/(100 xx 12)`
`7500 = (24 xx 25)/2 xx (2500 xx "Rate")/(100 xx 12)`
Rate = `(7500 xx 100 xx 24)/(24 xx 25 xx 2500)` = 12% p.a
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संबंधित प्रश्न
A page from the savings bank account of Mrs Ravi is given below.
| Date | Particulars | Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 3rd 2006 | B/F | 6000 | ||
| April 7th | By cash | 2300 | 8300 | |
| April 15th | By cheque | 3500 | 11800 | |
| May 20th | To self | 4200 | 7600 | |
| June 10th | By cash | 5800 | 13400 | |
| June 15th | To self | 3100 | 10300 | |
| August 13th | By cheque | 1000 | 11300 | |
| August 25th | To self | 7400 | 3900 | |
| September 6th 2006 |
By cash | 2000 | 5900 |
She closed the account on 30th September 2006. Calculate the interest Mrs Ravi earned
at the end of 30th September 2006 at 4.5% per annum interest. Hence, find the
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