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प्रश्न
Mr. Gupta opened a recurring deposit account in a bank. He deposited Rs. 2500 per month for two years. At the time of maturity he got Rs. 67,500. Find:
1) the total interest earned by Mr Gupta.
2) the rate of interest per annum.
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उत्तर
1) Monthly instalment = Rs. 2500
n = 24, Amount deposited = 2500 x 24 = Rs. 60000
Maturity value = Rs. 67500
Interest on his deposit = Rs. (67500 – 60000) = Rs. 7500
2) Now Interest = `("n"("n"+1))/2 xx ("Instalment" xx "Rate")/(100 xx 12)`
`7500 = (24 xx 25)/2 xx (2500 xx "Rate")/(100 xx 12)`
Rate = `(7500 xx 100 xx 24)/(24 xx 25 xx 2500)` = 12% p.a
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संबंधित प्रश्न
A page from the ‘Savings Bank’ account of Priyanka is given below:
| Date | Particulars |
Amount (Rs.) |
Amount deposited (Rs.) |
Balance (Rs.) |
| 03/04/2006 | B/F | 4000.00 | ||
| 05/04/2006 | By cash | 2000.00 | 6000.00 | |
| 18/04/2006 | By cheque | 6000.00 | 12000.00 | |
| 25/05/2006 | By cheque | 5000.00 | 7000.00 | |
| 30/05/2006 | By cash | 3000.00 | 10000.00 | |
| 20/07/2006 | By self | 4000.00 | 6000.00 | |
| 10/09/2006 | By cash | 2000.00 | 8000.00 | |
| 19/09/2006 | To cheque | 1000.00 | 7000.00 |
If the interest earned by Priyanka for the period ending September 2006 is Rs. 175, the find the rate of interest.
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Fill in the blanks in the table.
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| 4200 | 7% | 3 years | ...... | ...... |
Fill in the blanks in the table.
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| ...... | 5% | ...... | 6000 | 18000 |
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