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प्रश्न
A recurring deposit account of Rs. 1,200 per month has a maturity value of Rs. 12,440. If the rate of interest is 8% and the interest is calculated at the end of every month; find the time (in months) of this Recurring Deposit Account.
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उत्तर
Installment per month (P) = Rs. 1,200
Number of months (n) = n
Let rate of interest (r) = 8% p.a.
∴ `S.I. = P xx (n(n +1))/(2 xx 12) xx r/100`
= `1200 xx (n(n + 1))/(2 xx 12) xx 8/100`
= `1200 xx (n(n + 1))/24 xx 8/100`
= Rs. 4n(n + 1)
Maturity value = Rs. (1,200 × n) + Rs. 4n(n + 1)
= Rs. (1200n + 4n2 + 4n)
Given maturity value = Rs. 12,440
Then 1200n + 4n2 + 4n = 12,440
⇒ 4n2 + 1204n – 12440 = 0
⇒ n2 + 301n – 3110 = 0
⇒ (n + 311)(n – 10) = 0
⇒ n = – 311 or n = 10 months
Then number of months = 10
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संबंधित प्रश्न
Virat opened a Savings Bank account in a bank on 16th April 2010. His pass book shows the following entries:
| Date | Particulars |
Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 16, 2010 | , By cash | - | 2500 | 2500 |
| April 28th | By cheque | - | 3000 | 5500 |
| May 9th | To cheque | 850 | - | 4650 |
| May 15th | By cash | 1600 | 6250 | |
| May 24th | To cash | 1000 | - | 5250 |
| June 4th | To cash | 500 | - | 4750 |
| June 30th | To cheque | - | 2400 | 7150 |
| July 3rd | By cash | - | 1800 | 8950 |
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Ms. Chitra opened a saving bank account with SBI on 05.04.2007 with a cheque deposit of Rs 11,000/.Subsequently, she took out Rs 3,200/- on 12.05.2007; deposited a cheque of Rs. 8,800/- on 03.06.2007 and paid Rs 2,000/- by cheque on 18.06.2007.
If the rate of simple interest was 5% pa compounded at the end of March and September, find her balance on 1.04.2008
Fill in the blanks in the table.
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| ...... | 6% | 4 years | 1200 | ...... |
Fill in the blanks in the table.
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| 8000 | 5% | ...... | 800 | ...... |
