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प्रश्न
Fill in the blanks in the table.
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| ...... | 5% | ...... | 6000 | 18000 |
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उत्तर
Given:
Total Amount (A) = 18000 rupees
Total interest (I) = 6000 rupess
Formula:
Now, Principal (P) = Total Amount − Total interest
Solution:
Principal (P) = 18000 − 6000
= 12000 rupees
Rate of interest (R) = 5%
Time (T) = `("I"xx100)/("P"xx"R")`
= `(6000xx100)/(12000xx5)`
= 10 years
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| 12000 | 5% | 10 years | 6000 | 18000 |
संबंधित प्रश्न
Virat opened a Savings Bank account in a bank on 16th April 2010. His pass book shows the following entries:
| Date | Particulars |
Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 16, 2010 | , By cash | - | 2500 | 2500 |
| April 28th | By cheque | - | 3000 | 5500 |
| May 9th | To cheque | 850 | - | 4650 |
| May 15th | By cash | 1600 | 6250 | |
| May 24th | To cash | 1000 | - | 5250 |
| June 4th | To cash | 500 | - | 4750 |
| June 30th | To cheque | - | 2400 | 7150 |
| July 3rd | By cash | - | 1800 | 8950 |
Calculate the interest Virat earned at the end of 31st July 2010 at 4% per annum interest. What sum of money will he receive if he closed the account on 1st August 2010?
Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits Rs. 140 per month for 4 years. If he gets Rs. 8,092 on maturity, find the rate of interest given by the bank.
Mrs. Geeta deposited Rs. 350 per month in a bank for 1 year and 3 months under the Recurring Deposit Scheme. If the maturity value of her deposits is Rs. 5,565; find the rate of interest per annum.
Mr. Burman open a saving back account with Bank of India on 3rd April 2007 with a cash deposit of Rs 5,000/-. Subsequently, he deposited Rs 16,500/- by cheque on 11th April 2007, withdraw Rs 4,000/- on 10th May, paid Rs 3,500 for insurance by cheque on 7th July 2007, deposited Rs. 6,000/- in cash on 9th August 2007 and withdrew Rs 1,500/- on 12th Oct 2007.
Make the entries in his passbook
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