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Minimize :Z=6x+4y, Subject to : 3x+2y ≥12

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प्रश्न

Minimize :Z=6x+4y

Subject to : 3x+2y ≥12

x+y ≥5

0 ≤x ≤4

0 ≤ y ≤ 4 

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उत्तर

3x+2y ≥12

Points : (4, 0) and (0, 6), Non origin side

x+y ≥5

Points : (5, 9) and (0, 5), Non origin side

0 ≤x ≤4

Parallel to y-axis, point (4, 0), origin side

0 ≤ y ≤ 4 

Parallel to x-axis, point (0, 4), origin side

x ≥ 0, y ≥ 0
x-axis and y-axis, first quadrant only.

A is the intersection of 3x+2y =12 and y= 4

x=4/3 and y=4

A(4/3, 4)

B is intersection of 3x + 2 y = 12 and x + y= 5
x=2, y=3
B(2,3)

C is the intersection of x = 4 and x + y = 5
x=4, y=1
C(4,1)

D is the intersection of x = 4 and y = 4

D ( 4, 4)

End Points value of z=6x+4y
A(4/3, 4) 8+16=24
B(2, 3) 12+12=24
C(4, 1) 24+4=28
D(4, 4) 24+16=40


Z is minimum 24 on the segment AB joining A( 4/3 ,4) and (2,3)

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2013-2014 (March)

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