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Log[log(logx5)]

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प्रश्न

`log [log(logx^5)]`

योग
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उत्तर

Let y = `log [log(logx^5)]`

Differentiating both sides w.r.t. x

`"dy"/"dx" = "d"/"dx" log [log(log x^5)]`

= `1/(log(log x^5)) xx "d"/"dx" log (log x^5)`

= `1/(log(log x^5)) xx 1/(log(x^5)) xx "d"/"dx" log x^5`

= `1/(log(log x^5)) * 1/(log (x^5)) * 1/x^5 * "d"/"dx" x^5`

= `1/(log(log x^5)) * 1/(log(x^5)) * 1/x^5 * 5x^4`

= `5/(x log (x^5) * log (log x^5))`

Hence, `"dy"/"dx" = 5/(x log (x^5) * log (log x^5))`

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अध्याय 5: Continuity And Differentiability - Exercise [पृष्ठ १०९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 5 Continuity And Differentiability
Exercise | Q 28 | पृष्ठ १०९

वीडियो ट्यूटोरियलVIEW ALL [3]

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