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Differentiate the function with respect to x: xx + xa + ax + aa, for some fixed a > 0 and x > 0

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प्रश्न

Differentiate the function with respect to x:

xx + xa + ax + aa, for some fixed a > 0 and x > 0

योग
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उत्तर

Let, y = xx + xa + ax + aa

On differentiating with respect to x,

`dy/dx = d/dx (x^x) + d/dx (x^a) + d/dx (a^x) + (a^a) d/dx (1)`

= `d/dx (x^x) + ax^(a - 1) + a^x log a + 0`   ...(1)

Let, u = xx 

Taking log on both sides,

log u = x log x

On differentiating with respect to x,

`1/u (du)/dx = x d/dx log x + log x d/dx (x)`

= `x * 1/x + log x`

= (1 + log x)

∴ `(du)/dx` = u (1 + log x)

= xx (1 + log x)

i.e., `d/dx (x^x) = (du)/dx`

= xx (1 + log x)

Putting the value of `d/dx (x^x)` in equation (1),

`dy/dx` = xx (1 + log x) + axa − 1 + ax log a

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अध्याय 5: Continuity and Differentiability - Exercise 5.9 [पृष्ठ १९१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.9 | Q 10 | पृष्ठ १९१

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