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lim x → 0 sin 2 x ( cos 3 x − cos x ) x 3

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प्रश्न

\[\lim_{x \to 0} \frac{\sin 2x \left( \cos 3x - \cos x \right)}{x^3}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{\sin 2x \left( \cos 3x - \cos x \right)}{x^3} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{\sin 2x \times - 2 \sin\left( \frac{3x + x}{2} \right) \sin\left( \frac{3x - x}{2} \right)}{x^3} \right]\]
\[ = - 2 \lim_{x \to 0} \left[ \frac{\sin 2x}{2x} \times \frac{\sin 2x}{2x} \times \frac{\sin x}{x} \right] \times 2 \times 2\]
\[ = - 8\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५०]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 37 | पृष्ठ ५०

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