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प्रश्न
Let \[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\] Evaluate X for A = B = C = 0.
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उत्तर
Given:
Output
\[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\]
A = B = C = 0
\[X = 0 . ( \overline{{0 . 0)}} + 0( \overline{{0 . 0)}} + 0 . ( \overline{{0 . 0)}}\]
\[ = 0 . \bar{0} + 0 . \bar{0} + 0 . \bar{0}\]
\[ = 0 . 1 + 0 . 1 + 0 . 1\]
\[ = 0 + 0 + 0\]
\[ = 0\]
APPEARS IN
संबंधित प्रश्न
Which logic gate corresponds to the truth table given below?
|
A |
B |
Y |
|
0 |
0 |
I |
|
0 |
1 |
0 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
Write the truth table for the combination of the gates shown. Name the gates used.
The logic gate which produces LOW output when one of the input is HIGH and produces
HIGH output only when all of its inputs are LOW is called _______.
(A) AND gate
(B) OR gate
(C) NOR gate
(D) NAND gate
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- acts as OR gate while the circuit
- acts as AND gate.
(a)
(b)
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A logic circuit provides the output Y as per the following truth table:
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
The expression for the output Y is:
