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प्रश्न
Let \[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\] Evaluate X for A = B = C = 0.
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उत्तर
Given:
Output
\[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\]
A = B = C = 0
\[X = 0 . ( \overline{{0 . 0)}} + 0( \overline{{0 . 0)}} + 0 . ( \overline{{0 . 0)}}\]
\[ = 0 . \bar{0} + 0 . \bar{0} + 0 . \bar{0}\]
\[ = 0 . 1 + 0 . 1 + 0 . 1\]
\[ = 0 + 0 + 0\]
\[ = 0\]
APPEARS IN
संबंधित प्रश्न
Which logic gate corresponds to the truth table given below?
|
A |
B |
Y |
|
0 |
0 |
I |
|
0 |
1 |
0 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
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