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प्रश्न
Kiran deposited 200 per month for 36 months in a bank’s recurring deposit account. If the bank pays interest at the rate of 11% per annum, find the amount she gets on maturity.
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उत्तर
Interset = `("P"n(n +1) xx "R")/(2,400)`
= `(200 xx 36 xx 37 xx 11)/(2,400)`
= 3 x 37 x 11
= ₹ 1,221
Sum deposited = 36 x 200 = ₹ 7,200
Amount = 7,200 + 1,221 = ₹ 8,421.
संबंधित प्रश्न
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| 08.02.2008 | By Cash | 12000.00 | ||
| 15.03.2008 | To cash | 3000.00 | ||
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Amount Deposited (in ₹) |
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| Jan. 1 | By Balance | - | - | 2,100·00 |
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| Date Year 2004 |
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Amount (₹)Deposits |
Balance (₹) |
| January 1 | B/F | - | - | 2,000.00 |
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