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प्रश्न
Kiran deposited 200 per month for 36 months in a bank’s recurring deposit account. If the bank pays interest at the rate of 11% per annum, find the amount she gets on maturity.
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उत्तर
Interset = `("P"n(n +1) xx "R")/(2,400)`
= `(200 xx 36 xx 37 xx 11)/(2,400)`
= 3 x 37 x 11
= ₹ 1,221
Sum deposited = 36 x 200 = ₹ 7,200
Amount = 7,200 + 1,221 = ₹ 8,421.
संबंधित प्रश्न
Manish opens a Recurring Deposit Account with the Bank of Rajasthan and deposits Rs. 600 per month for 20 months. Calculate the maturity value of this account, if the bank pays interest at the rate of 10% per annum.
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(i) 15-05.2007; deposited Rs. 3,700
(ii) 27-07-2007; withdrew Rs. 2,400
(iii) 06-09-2007; withdrew Rs. 1,600
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(vi) 23-03-2008; account closed.
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| Feb. 3, 1981 | By cash | - | 500·00 | 500·00 |
| Feb, 11 | To cheque no. 371 | 200·00 | - | 300·00 |
| Feb. 11 | By cheque | - | 700·00 | 1,000·00 |
| March 1 | By salary | - | 2,350·00 | 3,350·00 |
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Deposits (₹) |
Balance (₹) |
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| 07-01-05 | By cash | 500·00 | 1,700·00 | |
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| 10-02-05 | By cash | - | 800·00 | 2,100·00 |
| 25-09-05 | By cheque | 500·00 | - | 1,600·00 |
| 20-09-05 | By cash | - | 700·00 | 2,300·00 |
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| 05-12-05 | By cash | - | 300·00 | 2,000·00 |
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