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Integrate the function: x2+4x+1

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प्रश्न

Integrate the function:

`sqrt(x^2 + 4x +1)`

योग
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उत्तर

Let `I = int sqrt(x^2 + 4x + 1)`  dx

`= int sqrt((x^2 + 4x + 4) - 3)`  dx

`= int sqrt((x + 2)^2 - (sqrt3)^2)` dx

`= ((x + 2))/2 sqrt((x + 2)^2 - 3) - 3/2  log abs ((x + 2) + sqrt ((x + 2)^2 + 3)) + C`           `...[∵ sqrt (x^2 - a^2) dx = x/2 sqrt (x^2 - a^2) - a^2/2 log |x + sqrt (x^2 - a^2)| + C]`

`= ((x + 2))/2 sqrt(x^2 + 4x + 1) - 3/2 log  abs((x + 2) + sqrt(x^2 + 4x + 1)) + C`

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अध्याय 7: Integrals - Exercise 7.7 [पृष्ठ ३३०]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.7 | Q 4 | पृष्ठ ३३०

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