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Integrate the function: 4-x2

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प्रश्न

Integrate the function:

`sqrt(4 - x^2)`

योग
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उत्तर

Let `I = int sqrt (4 - x^2)  dx`

`= int sqrt ((2)^2 - x^2) dx`

`= [x /2 sqrt ((2)^2 - x^2) + 4/2 sin^-1 (x/2)] + C`           `...[int sqrt (a^2 - x^2) dx = x/2 sqrt (a^2 - x^2) + a^2/2 sin^-1 (x/a) + C]`

`= (x sqrt 4 - x^2)/2 + 4/2 sin^-1 (x/2) +C`

`(x sqrt(4 - x^2))/2 + 2 sin^-1 (x/2) + C`

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अध्याय 7: Integrals - Exercise 7.7 [पृष्ठ ३३०]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.7 | Q 1 | पृष्ठ ३३०

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