Advertisements
Advertisements
प्रश्न
In Young's double slit experiment, the distance of the 4th bright fringe from the centre of the interference pattern is 1.5 mm. The distance between the slits and the screen is 1.5 m, and the wavelength of light used is 500 nm. Calculate the distance between the two slits.
Advertisements
उत्तर
Given that D = 1.5 m, λ = 500 nm = 500 × 10-9 m, n = 4, d = ?
In, YDSE, the formula for bright fringes (constructive interference) is
`"Y"_"n" = ("n"lambda"D")/"d"`
`Delta"Y" = (4 xx 500 xx 10^-9 xx 1.5)/"d" = 1.5 xx 10^-3`
⇒ `"d" = (4 xx 50 xx 10^-9 xx 1.5)/(1.5 xx 10^-3)`
⇒ d = 200 × 10-6 m
APPEARS IN
संबंधित प्रश्न
A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young’s double-slit experiment.
Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm.
In a Young's double slit experiment, two narrow vertical slits placed 0.800 mm apart are illuminated by the same source of yellow light of wavelength 589 nm. How far are the adjacent bright bands in the interference pattern observed on a screen 2.00 m away?
A Young's double slit apparatus has slits separated by 0⋅28 mm and a screen 48 cm away from the slits. The whole apparatus is immersed in water and the slits are illuminated by red light \[\left( \lambda = 700\text{ nm in vacuum} \right).\] Find the fringe-width of the pattern formed on the screen.
In a Young's double slit interference experiment, the fringe pattern is observed on a screen placed at a distance D from the slits. The slits are separated by a distance d and are illuminated by monochromatic light of wavelength \[\lambda.\] Find the distance from the central point where the intensity falls to (a) half the maximum, (b) one-fourth the maximum.
What should be the path difference between two waves reaching a point for obtaining constructive interference in Young’s Double Slit experiment ?
Write the conditions on path difference under which constructive interference occurs in Young’s double-slit experiment.
In Young’s double slit experiment, what should be the phase difference between the two overlapping waves to obtain 5th dark band/fringe on the screen?
Draw the intensity distribution as function of phase angle when diffraction of light takes place through coherently illuminated single slit.
A beam of light consisting of two wavelengths 600 nm and 500 nm is used in Young's double slit experiment. The silt separation is 1.0 mm and the screen is kept 0.60 m away from the plane of the slits. Calculate:
- the distance of the second bright fringe from the central maximum for wavelength 500 nm, and
- the least distance from the central maximum where the bright fringes due to both wavelengths coincide.
What path difference produces a bright fringe?
