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प्रश्न
In the given figure, RS is a diameter of the circle. NM is parallel to RS and ∠MRS = 29°. Calculate : ∠RNM
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उत्तर
Join RN and MS.
∴ ∠RMS = 90°
(Angle in a semicircle is a right angle)
∴ ∠RSM = 90° – 29° = 61°
(By angle sum property of triangle RMS)
∴ ∠RNM = 180° ∠RSM = 180° – 61° = 119°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
संबंधित प्रश्न
In the figure, m∠DBC = 58°. BD is the diameter of the circle. Calculate:
1) m∠BDC
2) m∠BEC
3) m∠BAC
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In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and ∠DCB = 120°.
Calculate : ∠DBC
Also, show that the ΔAOD is an equilateral triangle.
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Also, show that the ΔAOD is an equilateral triangle.
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Calculate:
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