Question

In the given figure, PT ∥ QR and QT ∥ RS. Show that: area of ΔPQR = area of ΔTQS.

*Question modified

Answer 1

Joining TR, we get

ΔPQR and ΔQTR are on the same base QR and between the same parallel lines QR and PT.
∴ A(ΔPQR) = A(ΔQTR)  ....(i)
ΔQTR and ΔTQS are on the same base QT and between the same parallel lines QT and RS.
∴ A(ΔQRT) = A(ΔTQS)  ....(ii)
From (i) and (ii), we get
A(ΔPQR) = A(ΔTQS).