Advertisements
Advertisements
प्रश्न
In the following figure, ratio of the area of triangle ABC to the area of triangle ACD is the same as the ratio of base BC of triangle ABC to the base CD of triangle ACD.
विकल्प
True
False
Advertisements
उत्तर
This statement is True.
Explanation:
Area of a triangle ABC = `1/2 xx BC xx AC`
Area of a triangle ACD = `1/2 xx CD xx AC`
Now, their ratio = `(1/2 xx BC xx AC)/(1/2 xx CD xx AC)`
= `(BC)/(CD)` or BC : CD
APPEARS IN
संबंधित प्रश्न
In Fig. 8, the vertices of ΔABC are A(4, 6), B(1, 5) and C(7, 2). A line-segment DE is drawn to intersect the sides AB and AC at D and E respectively such that `(AD)/(AB)=(AE)/(AC)=1/3 `Calculate th area of ADE and compare it with area of ΔABCe.
The vertices of ΔABC are (−2, 1), (5, 4) and (2, −3) respectively. Find the area of the triangle and the length of the altitude through A.
Find the area of ΔABC whose vertices are A(–5, 7), B(–4, –5) and C(4, 5).
For what value of y, are the points P(1, 4), Q(3,y) and R(-3, 16) are collinear ?
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
In a triangle ABC, if `|(1, 1, 1),(1 + sin"A", 1 + sin"B", 1 + sin"C"),(sin"A" + sin^2"A", sin"B" + sin^2"B", sin"C" + sin^2"C")|` = 0, then prove that ∆ABC is an isoceles triangle.
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.
If `D((-1)/2, 5/2), E(7, 3)` and `F(7/2, 7/2)` are the midpoints of sides of ∆ABC, find the area of the ∆ABC.
The area of a triangle with vertices A, B, C is given by ______.
In the following figure, area of ΔPQR is 20 cm2 and area of ΔPQS is 44 cm2. Find the length RS, if PQ is perpendicular to QS and QR is 5 cm.
