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प्रश्न
In the following diagram an arrow shows the motion of the coil towards the bar magnet.
(1) State in which direction the current flows, A to B or B to A?
(2) Name the law used to come to the conclusion.
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उत्तर
(1) The direction of current in the coil is from A to B.
(2) The law used is the Lenz’s law of electromagnetic induction.
The coil is moving towards the North Pole of the magnet. Due to this, there is a change in magnetic flux in the coil. Now, the direction of induced e.m.f. (induced current) is such that it opposes this change in flux. Hence, the right end of the coil should also behave as North Pole. Hence, the current will be in the anti-clockwise direction, i.e., from A to B.
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संबंधित प्रश्न
State Lenz’s Law.
- Describe briefly one way producing an induced e.m.f?
- State one factor that determines the magnitude of induced e.m.f. in part (a) above.
- What factor determines the direction of induced e.m.f. in part (a) above?
What is Lenz’s law?
A coil of 25 turns is pulled in 0.05 s between the poles of a magnet, where its area includes `21 xx106-6 "Wb" "to" 1 xx 10^-6 "Wb"`. The average e.m.f. is ______.
Magnetic flux passing through a coil is initially 6 x 10-4 Wb. It reduces to 10 % of its original value in 't' second. If the e.m.f. induced is 0.54 mV then 't' in second is ____________.
A magnet is moved towards a coil (i) quickly (ii) slowly. The induced potential difference.
A.C generator works on the principle of ____________.
A D.C generator works on the principle of ____________.
Express Faraday-Lenz's law of electromagnetic induction in an equation form.
The magnetic flux through a coil perpendicular to its plane is varying according to the relation Φ = (5t3 + 4t2 + 2t − 5) Weber. If the resistant of the coil is 5 ohm, then the induced current through the coil at t = 2 sec will be ______.
