हिंदी

In a Survey It Was Found that 21 Persons Liked Product P1, 26 Liked Product P2 and 29 Liked Product P3. If 14 Persons Liked Products P1 and P2;

Advertisements
Advertisements

प्रश्न

In a survey it was found that 21 persons liked product P1, 26 liked product P2 and 29 liked product P3. If 14 persons liked products P1 and P2; 12 persons liked product P3 and P1 ; 14 persons liked products P2 and P3 and 8 liked all the three products. Find how many liked product P3 only.

Advertisements

उत्तर

Let \[P_1 , P_2 \text{ and } P_3\] denote the sets of persons liking products\[P_1 , P_2 \text{ and } P_3\] respectively.
Also, let U be the universal set.
Thus, we have:

n( \[P_1\]= 21, n(\[P_2\]= 26 and n(\[P_3\] 29
And,
n(\[P_1\]\[\cap\]\[P_3\]= 12, n(\[P_2 \cap P_3\]n(\[P_1 \cap P_2 \cap P_3\]= 8 

Now,
Number of people who like only product \[P_3\] 

= `n (P_3∩ P_1′∩ P_2′)` 

= `n {P_3∩ (P_1∪  P_2)′}`

\[ = n \left( P_3 \right) - n\left[ P_3 \cap \left( P_1 \cup P_2 \right) \right]\]

\[ = n\left( P_3 \right) - n\left[ \left( P_3 \cap P_1 \right) \cup \left( P_3 \cap P_2 \right) \right]\]

\[ = n\left( P_3 \right) - \left[ n\left( P_3 \cap P_1 \right) + n\left( P_3 \cap P_2 \right) - n\left( P_1 \cap P_2 \cap P_3 \right) \right]\]

\[ = 29 - \left( 12 + 14 - 8 \right)\]

\[ = 11\]

Therefore, the number of people who like only product \[P_3\]is 11 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Sets - Exercise 1.08 [पृष्ठ ४७]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 1 Sets
Exercise 1.08 | Q 15 | पृष्ठ ४७

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

What universal set (s) would you propose for the following:

The set of right triangles.


What universal set (s) would you propose for the following:

The set of isosceles triangles.


Given the sets, A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}, the following may be considered as universal set (s) for all the three sets A, B and C?

Φ


Given the sets, A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}, the following may be considered as universal set (s) for all the three sets A, B and C?

{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}


Given the sets A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}, the following may be considered as universal set (s) for all the three sets A, B and C?

{1, 2, 3, 4, 5, 6, 7, 8}


If \[X = \left\{ 8^n - 7n - 1: n \in N \right\} \text{ and } Y = \left\{ 49\left( n - 1 \right): n \in N \right\}\] \[X \subseteq Y .\]


For any two sets A and B, prove that 

 B ⊂ A ∪ B         


For any two sets A and B, prove that 

A ∩ ⊂ A             


For any two sets A and B, prove that A ⊂ ⇒ A ∩ 


For any two sets, prove that: 

\[A \cup \left( A \cap B \right) = A\] 

 


For any two sets, prove that: 

\[A \cap \left( A \cup B \right) = A\]


For any two sets A and B, prove that: \[A \cap B = \phi \Rightarrow A \subseteq B'\] 


For any two sets of A and B, prove that: 

\[A' \cup B = U \Rightarrow A \subset B\] 


Is it true that for any sets A and \[B, P \left( A \right) \cup P \left( B \right) = P \left( A \cup B \right)\]? Justify your answer.


Show that for any sets A and B, A ∪ (B – A) = (A ∪ B)


For any two sets A and B, prove the following: 

\[A \cap \left( A' \cup B \right) = A \cap B\] 


For any two sets A and B, prove the following: 

\[A - \left( A - B \right) = A \cap B\]


For any two sets A and B, prove the following:

\[A - B = A \Delta\left( A \cap B \right)\]


Let A and B be two sets such that : \[n \left( A \right) = 20, n \left( A \cup B \right) = 42 \text{ and } n \left( A \cap B \right) = 4\] \[n \left( A - B \right)\]


In a group of 950 persons, 750 can speak Hindi and 460 can speak English. Find: 

how many can speak English only. 


Let A and B be two sets in the same universal set. Then,\[A - B =\]


If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8} and D = {7, 8, 9, 10}; find

A ∪ B ∪ D


If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8} and D = {7, 8, 9, 10}; find

B ∪ C ∪ D


If A and B are subsets of the universal set U, then show that A ⊂ A ∪ B


If A and B are subsets of the universal set U, then show that (A ∩ B) ⊂ A


In a town of 10,000 families it was found that 40% families buy newspaper A, 20% families buy newspaper B, 10% families buy newspaper C, 5% families buy A and B, 3% buy B and C and 4% buy A and C. If 2% families buy all the three newspapers. Find the number of families which buy none of A, B and C


The set (A ∩ B′)′ ∪ (B ∩ C) is equal to ______.


If A = {1, 3, 5, 7, 9, 11, 13, 15, 17} B = {2, 4, ..., 18} and N the set of natural numbers is the universal set, then A′ ∪ (A ∪ B) ∩ B′) is ______.


Given the sets A = {1, 3, 5}. B = {2, 4, 6} and C = {0, 2, 4, 6, 8}. Then the universal set of all the three sets A, B and C can be ______.


For all sets A and B, A – (A ∩ B) is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×