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प्रश्न
In a rectangle ABCD, prove that ∆ACB ≅ ∆CAD.
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उत्तर
In ∆ACB and ∆CAD:
AB = CD (rectangle property)
AD = BC (rectangle property)
AC ( common side )
Hence, by SSS criterion, it is proved that\[∆ ACB \cong ∆ CAD\]
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