Advertisements
Advertisements
प्रश्न
In an examination the ratio of the number of suo:essful candidates to unsuccessful candidates is 7:5. Had 30 more appeared and 10 more passed, the ratio of successful candidates to unsuccessful candidates would have been 4:3. Find the number of candidates who appeared in the examination originally.
Advertisements
उत्तर
Let successful candidates be 7x and unsuccessful candidates be 5x.
Now , `(7"x" + 10)/(5"x" + 20) = 4/3`
⇒ 21x + 30 = 20x + 80
⇒ x = 50
7x = 7 x 50 = 350
5x = 5x50 = 250
.·. 7x + 5x = 350 + 250 = 600
Therefore, there were 600 candidates originally.
APPEARS IN
संबंधित प्रश्न
Find the ratio compounded of the duplicate ratio of 5 : 6, the reciprocal ratio of 25 : 42 and the sub-duplicate ratio of 36 : 49.
The ratio between the number of boys and the number of girls in a class is 4:3 . If there were 20 more boys and 12 less girls, the ratio would have been 2:1. Find the total number of students in
the class.
Find the compounded ratio of the following:
(m-n):(m+n), (m+n)2 : (m2+n2) and (m4 - n4): (m2-n2) 2
Express the given ratio in its simplest form: 1.5 : 2.5
Express the given ratio in its simplest form: 6 months: `1 1/3` years
A rectangular field is 100 m by 80 m. Find the ratio of length to its breadth.
If (4x + 3y) : (3x + 5y) = 6 : 7, find y, if x = 27
Shubham’s age today is 12 years and his father’s is 42 years. Shubham’s mother is younger than his father by 6 years. Find the ratio of Shubham’s age to his mother’s age when Shubham was 10 years old.
Find two numbers in the ratio of 8 : 7 such that when each is decreased by , they are in the ratio 11 : 9.
To find the ratio of two quantities, they must be expressed in _____ units.
