Advertisements
Advertisements
प्रश्न
In an exhibition hall, there are 24 display boards each of length 1 m 50 cm and breadth 1 m. There is a 100 m long aluminium strip, which is used to frame these boards. How many boards will be framed using this strip? Find also the length of the aluminium strip required for the remaining boards.
Advertisements
उत्तर
Given, total display boards = 24
Length of one display boards = 1 m + 50 cm
= 1 m + `50/100` m ...[∵ 1 m = 100 cm]
= (1 + 0.5) m
= 1.5 m
Breadth of one display board = 1 m
∴ Perimeter of one display board = 2 × (Length + Breadth)
= 2 × (1.5 + 1) m
= 2 × 2.5 m
= 5 m
Length of strip = 100 m ...[Given]
Now, number of boards will be framed
= `"Length of strip"/"Perimeter of one board"`
= `100/5`
= 20
This means that out of 24 only 20 boards will be framed.
Number of board left unframed = 24 – 20 = 4
∴ Length of the strip required for remaining boards
= 4 × Perimeter of one board
= 4 × 2(1.5 + 1)
= 4 × 2 × 2.5
= 20 m
APPEARS IN
संबंधित प्रश्न
The side of a square is of length 20 mm. Find its perimeter in cm.
Find the perimeter of the following figure:
If a square of side 1 cm is cut out of the corner of a larger square with side 3 cm (see the figure), what will be the perimeter of the remaining shape?
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 10 m | ? | ? | 120 sq.m |
How much wire will be needed to make a rectangle of length 6 cm and breadth 3 cm?
If we take 2 rounds of a field, that is 340 m long and 160 m wide. Find the distance covered in kilometers?
Chumki, Jhumri, and Imran need wire to make a fence.
- Who will need the longest wire for fencing?
To find the cost of a frame of a picture, we need to find the perimeter of the picture.
Find all the possible dimensions (in natural numbers) of a rectangle with an area of 36 sq cm, and find their perimeters.
Find the perimeter of the following figure:
