Advertisements
Advertisements
प्रश्न
In an exhibition hall, there are 24 display boards each of length 1 m 50 cm and breadth 1 m. There is a 100 m long aluminium strip, which is used to frame these boards. How many boards will be framed using this strip? Find also the length of the aluminium strip required for the remaining boards.
Advertisements
उत्तर
Given, total display boards = 24
Length of one display boards = 1 m + 50 cm
= 1 m + `50/100` m ...[∵ 1 m = 100 cm]
= (1 + 0.5) m
= 1.5 m
Breadth of one display board = 1 m
∴ Perimeter of one display board = 2 × (Length + Breadth)
= 2 × (1.5 + 1) m
= 2 × 2.5 m
= 5 m
Length of strip = 100 m ...[Given]
Now, number of boards will be framed
= `"Length of strip"/"Perimeter of one board"`
= `100/5`
= 20
This means that out of 24 only 20 boards will be framed.
Number of board left unframed = 24 – 20 = 4
∴ Length of the strip required for remaining boards
= 4 × Perimeter of one board
= 4 × 2(1.5 + 1)
= 4 × 2 × 2.5
= 20 m
APPEARS IN
संबंधित प्रश्न
The length of a rectangular field is 30 m and its diagonal is 34 m. Find the breadth of the field and its perimeter.
The perimeters of two squares are in the ratio 8 : 15, find the ratio between the lengths of their sides.
The sides of a rectangle are 5 cm and 3 cm respectively. Find its area in mm2.
If we take 2 rounds of a field, that is 340 m long and 160 m wide. Find the distance covered in kilometers?
What is its perimeter __________
Match the shapes (each sides measures 2 cm) in column I with the corresponding perimeters in column II:
| Column I | Column II |
(A)  |
(i) 16 cm |
(B)  |
(ii) 20 cm |
(C)  |
(iii) 24 cm |
(D)  |
(iv) 28 cm |
| (v) 32 cm |
Perimeter of a regular octagon of side 6 cm is 36 cm.
Four regular hexagons are drawn so as to form the design as shown in the following figure. If the perimeter of the design is 28 cm, find the length of each side of the hexagon.
Find the perimeter of the following figure:
Find the perimeter of the following figure:
