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प्रश्न
In a single slit diffraction experiment, the width of the slit is increased. How will the
- size and
- intensity
of central bright band be affected? Justify your answer.
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उत्तर
The width of the central bright band = `2 D xx lambda/d`
Where d = width of the slit
- As the width of the slit is doubled, the size of the central diffraction band will be half.
- Intensity of the central bright band is proportional to d2.
So, the intensity will quadruple.
संबंधित प्रश्न
Estimate the distance for which ray optics is good approximation for an aperture of 4 mm and wavelength 400 nm.
In a single slit diffraction experiment, when tiny circular obstacle is placed in path of light from a distance source, a bright spot is seen at the centre of the shadow of the obstacle. Explain why?
Will the diffraction effects from a slit be more or less clearly visible if the slit-width is increased?
What appears at the centre of the single-slit diffraction pattern?
What appears on either side of the central maximum?
What separates the bright regions in a single-slit diffraction pattern?
What are the path differences between wavelets arriving at C when \[\theta=0\]?
What path difference between corresponding rays from the two equal halves of the slit causes them to cancel?
Why are secondary maxima much weaker than the central maximum?
What happens to the intensity of the secondary maxima as \[n\] increases?
