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In a certain bottling industry the quality control inspector recorded the weight of each of the 5 bottles selected at random during each hour of four hours in the morning. Time Weight in

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प्रश्न

In a certain bottling industry the quality control inspector recorded the weight of each of the 5 bottles selected at random during each hour of four hours in the morning.

Time Weight in ml
8:00 AM 43 41 42 43 41
9:00 AM 40 39 40 39 44
10:00 AM 42 42 43 38 40
11:00 AM 39 43 40 39 42
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योग
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उत्तर

Time Weight in ml `bar"X"` R
8:00 AM 43 41 42 43 41 42 2
9:00 AM 40 39 40 39 44 40.4 5
10:00 AM 42 42 43 38 40 41 5
11:00 AM 39 43 40 39 42 40.6 4
Total 164 16

The control limits for `bar"X"` chart is

`\overset{==}{"X"} = (sumbar"X")/"Number of samples" = 164/4` = 41

`bar"R" = 16/4` = 4

UCL = `\overset{==}{"X"} - "A"_2 bar"R"`

= 41 + (0.58)(4)

41 + 2.32 = 43.32

CL = `\overset{==}{"X"}` = 41

LCL = `\overset{==}{"X"} - "A"_2 bar"R"`

= 41 – (0.58)(4)

= 41 – 2.32

= 38.68

The control limits for range chart is

UCL = `"D"_4 bar"R"` = 2.115(4)

= 8.46

CL = `bar"R"` = 4

LCL = `"D"_2 bar"R"` = 0(4) = 0

Conclusion: Since all the points of sample mean and Range are within the control limits, the process is in control.

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Statistical Quality Control (SQC)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Applied Statistics - Exercise 9.3 [पृष्ठ २२८]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 9 Applied Statistics
Exercise 9.3 | Q 21 | पृष्ठ २२८

संबंधित प्रश्न

Define R chart


What are the uses of statistical quality control?


Write the control limits for the R chart


Construct `bar"X"` and R charts for the following data:

Sample Number  Observations 
1 32 36 42
2 28 32 40
3 39 52 28
4 50 42 31
5 42 45 34
6 50 29 21
7 44 52 35
8 22 35 44

(Given for n = 3, A2 = 1.023, D3 = 0 and D4 = 2.574)


Choose the correct alternative:

How many causes of variation will affect the quality of a product?


Choose the correct alternative:

The assignable causes can occur due to


Choose the correct alternative:

R is calculated using


From the following data, calculate the control limits for the mean and range chart.

Sample No. 1 2 3 4 5 6 7 8 9 10
Sample
Observations
50 21 50 48 46 55 45 50 47 56
55 50 53 53 50 51 48 56 53 53
52 53 48 50 44 56 53 54 549 55
49 50 52 51 48 47 48 53 52 54
54 46 47 53 47 51 51 47 54 52

The following data gives the average life(in hours) and range of 12 samples of 5lamps each. The data are

Sample No 1 2 3 4 5 6
Sample Mean 1080 1390 1460 1380 1230 1370
Sample Range 410 670 180 320 690 450
Sample No 7 8 9 10 11 12
Sample Mean 1310 1630 1580 1510 1270 1200
Sample Range 380 350 270 660 440 310

Construct control charts for mean and range. Comment on the control limits.


The following are the sample means and I ranges for 10 samples, each of size 5. Calculate; the control limits for the mean chart and range chart and state whether the process is in control or not.

Sample Number 1 2 3 4 5 6 7 8 9 10
Mean 5.10 4.98 5.02 4.96 4.96 5.04 4.94 4.92 4.92 4.98
Range 0.3 0.4 0.2 0.4 0.1 0.1 0.8 0.5 0.3 0.5

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