हिंदी

If y=sin(x+9)cosx then dydx at x = 0 is ______.

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प्रश्न

If `y = (sin(x + 9))/cosx` then `(dy)/(dx)` at x = 0 is ______.

विकल्प

  • cos 9

  • sin 9

  • 0

  • 1

MCQ
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उत्तर

If `y = (sin(x + 9))/cosx` then `(dy)/(dx)` at x = 0 is cos 9.

Explanation:

Given `y = (sin(x + 9))/cosx`

`(dy)/(dx) = (cosx * cos(x + 9) - sin(x + 9)(- sin x))/(cos^2x)`

= `(cos x cos(x + 9) + sin x sin(x + 9))/(cos^x)`

= `(cos(x + 9 - x))/(cos^2x)`

= `cos9/(cos^2x)`

∴ `((dy)/(dx))_("at"  x = 0) = cos9/(cos^2 0)`

= `cos9/(1)^2`

= cos 9

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अध्याय 13: Limits and Derivatives - Exercise [पृष्ठ २४५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 13 Limits and Derivatives
Exercise | Q 72 | पृष्ठ २४५

वीडियो ट्यूटोरियलVIEW ALL [1]

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