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If Y = Sin -1 ((8x)/(1 + 16x^2)), Find (Dy)/(Dx)

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प्रश्न

If y = sin -1 `((8x)/(1 + 16x^2))`, find `(dy)/(dx)`

योग
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उत्तर

y = sin-1  `((8x)/(1 + 16x^2))`

y = sin-1  `( (2(4x))/(1 + (4x)^2))`

Put 4x = tan θ `therefore` = tan-1 (4x)

y = sin-1 `((2 tan θ)/(1 + tan^2 θ))`

y = sin-1 (sin 2θ)

y = 2θ

y = 2 tan-1 (4x)

`(dy)/(dx) = 2/(1 + (4x^2)` . 4

`(dy)/(dx) = 8/(1 + 16x^2)`

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2016-2017 (July) Set 1

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