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If x and y are connected parametrically by the equations, without eliminating the parameter, find dy/dx. x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ)

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प्रश्न

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ)

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उत्तर

Here x = a (cos θ + θ sin θ) ...(1)

y = y = a (sin θ – θ cos θ) ...(2)

Differentiating (1) and (2) w.r.t. θ, we get

`dx/(d θ)` = a [−sin θ + θ × cos θ + sin θ]

= a  θ cos θ

`dy/(d theta)` = a [cos θ − (θ (−sin θ) + cos θ)]

= a [cos θ + θ sin θ − cos θ]

= a θ sin θ

`dy/dx = (dy/(dθ))/(dx/(dθ))`

= `(a θ sin θ)/(a θ cos θ)`

= tan θ

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.6 [पृष्ठ १८१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.6 | Q 10 | पृष्ठ १८१

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