हिंदी

If x = f(t), y = g(t) are differentiable functions of parammeter ‘ t ’ then prove that y is a differentiable function of 'x' and  hence, find dy/dx if x=a cost, y=a sint

Advertisements
Advertisements

प्रश्न

If x = f(t), y = g(t) are differentiable functions of parammeter ‘ t ’ then prove that y is a differentiable function of 'x' and  hence, find dy/dx if x=a cost, y=a sint

Advertisements

उत्तर

Given x=f(t),y=g(t) are differentiable function of parameter 't'

x=acost and y=asint

find dy/dx=?

x=acost

differentiate x w.r.t 't'

`dx/dt=d/dt(acost)`

`dx/dt=asint................(1)`

`y=asint`

`dy/dt=d/dt (asint)`

`dy/dt=-acost.............(2)`

dividing equation 2 by 1

`(dy/dt)/(dx/dt)=(-acost)/(asint)=-cost/sint......(3)`

`now " "x=acost`

`therefore cost=x/a`

`y=asint`

`therefore sintt=y/a`

from equation 3

`dy/dx=-(x/a)/(y/a)=-x/y`

 

 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (October)

APPEARS IN

संबंधित प्रश्न

If  `log_10((x^3-y^3)/(x^3+y^3))=2 "then show that"  dy/dx = [-99x^2]/[101y^2]`


If `ax^2+2hxy+by^2=0` , show that `(d^2y)/(dx^2)=0`


If x=α sin 2t (1 + cos 2t) and y=β cos 2t (1cos 2t), show that `dy/dx=β/αtan t`


If x = a sin 2t (1 + cos2t) and y = b cos 2t (1 – cos 2t), find the values of  `dy/dx `at t = `pi/4`


If x = a sin 2t (1 + cos 2t) and y = b cos 2t (1 – cos 2t) then find `dy/dx `

 


Find the value of `dy/dx " at " theta =pi/4 if x=ae^theta (sintheta-costheta) and y=ae^theta(sintheta+cos theta)`


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 2at2, y = at4


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a cos θ, y = b cos θ


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = sin t, y = cos 2t


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = cos θ – cos 2θ, y = sin θ – sin 2θ


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (θ – sin θ), y = a (1 + cos θ)


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

`x = (sin^3t)/sqrt(cos 2t), y = (cos^3t)/sqrt(cos 2t)`


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a sec θ, y = b tan θ


If `x = acos^3t`, `y = asin^3 t`,

Show that `(dy)/(dx) =- (y/x)^(1/3)`


If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find `dy/dx` when `theta = pi/3`


IF `y = e^(sin-1x)   and  z =e^(-cos-1x),` prove that `dy/dz = e^x//2`


The cost C of producing x articles is given as C = x3-16x2 + 47x.  For what values of x, with the average cost is decreasing'?  


x = `"t" + 1/"t"`, y = `"t" - 1/"t"`


x = `"e"^theta (theta + 1/theta)`, y= `"e"^-theta (theta - 1/theta)`


sin x = `(2"t")/(1 + "t"^2)`, tan y = `(2"t")/(1 - "t"^2)`


x = `(1 + log "t")/"t"^2`, y = `(3 + 2 log "t")/"t"`


If x = ecos2t and y = esin2t, prove that `"dy"/"dx" = (-y log x)/(xlogy)`


Differentiate `x/sinx` w.r.t. sin x


Differentiate `tan^-1 ((sqrt(1 + x^2) - 1)/x)` w.r.t. tan–1x, when x ≠ 0


If x = t2, y = t3, then `("d"^2"y")/("dx"^2)` is ______.


Derivative of x2 w.r.t. x3 is ______.


If y `= "Ae"^(5"x") + "Be"^(-5"x") "x"  "then"  ("d"^2 "y")/"dx"^2` is equal to ____________.


If x = `a[cosθ + logtan  θ/2]`, y = asinθ then `(dy)/(dx)` = ______.


Let a function y = f(x) is defined by x = eθsinθ and y = θesinθ, where θ is a real parameter, then value of `lim_(θ→0)`f'(x) is ______.


Under what condition is the formula \(\frac{dy}{dx}=\frac{dy/dt}{dx/dt}\) directly applicable?


Which formula is used after finding \(\frac{dx}{dt}\) and \(\frac{dy}{dt}\)?


For \(x=a\cos^3\theta\) and \(y=a\sin^3\theta\), which equation do these parametric equations represent?


For \(x=a\cos^3\theta\) and \(y=a\sin^3\theta\), what is \(\frac{dy}{dx}\) in terms of \(\theta\)?


The formula \(\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}\) is based on which rule?


What should always be checked before using the main formula for the derivative of parametric functions?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×