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If x and y are connected parametrically by the equations, without eliminating the parameter, find dy/dx. x = 2at^2, y = at^4

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प्रश्न

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 2at2, y = at4

योग
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उत्तर

Given, x = 2at ....(i)

and y = at ....(ii)

Differentiating (i) and (ii) w.r.t. t, we get

`dx/dt = 2a d/dt (t^2)`

= 2a × 2t

= 4at

And `dy/dt = a d/dt t^4`

= a × 4t3

= 4at3

∴ `dy/dx = (dy/dt)/(dx/dt)`

= `(4at^3)/(4at)`

= t2

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.6 [पृष्ठ १८१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.6 | Q 1 | पृष्ठ १८१

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